x^2+350x+15000=0

Solution for x^2+350x+15000=0 equation:

x^2+350x+15000=0

a = 1; b = 350; c = +15000;
Δ = b2-4ac
Δ = 3502-4·1·15000
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{62500}=250$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-250}{2*1}=\frac{-600}{2}
=-300
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+250}{2*1}=\frac{-100}{2}
=-50
$